3x^2+1x-80=0

Solution for 3x^2+1x-80=0 equation:

Simplifying
3x2 + 1x + -80 = 0

Reorder the terms:
-80 + 1x + 3x2 = 0

Solving
-80 + 1x + 3x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(-16 + -3x)(5 + -1x) = 0

Subproblem 1
Set the factor '(-16 + -3x)' equal to zero and attempt to solve:

Simplifying
-16 + -3x = 0

Solving
-16 + -3x = 0

Move all terms containing x to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + -3x = 0 + 16

Combine like terms: -16 + 16 = 0
0 + -3x = 0 + 16
-3x = 0 + 16

Combine like terms: 0 + 16 = 16
-3x = 16

Divide each side by '-3'.
x = -5.333333333

Simplifying
x = -5.333333333
Subproblem 2
Set the factor '(5 + -1x)' equal to zero and attempt to solve:

Simplifying
5 + -1x = 0

Solving
5 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -1x = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -1x = 0 + -5
-1x = 0 + -5

Combine like terms: 0 + -5 = -5
-1x = -5

Divide each side by '-1'.
x = 5

Simplifying
x = 5
Solution
x = {-5.333333333, 5}